Q1: The Henry's law constant (KH) values of three gases (A, B,
C) in water are 145,2 × 10−5 and
35kbar respectively. The solubility of these gases in water follow the
order: (NEET2024)
(a) B > A > C
(b) B > C > A
(c) A > C > B
(d) A > B > C Ans: (b)
Explanation video in tamil language
According to Henry's law,
the solubility of a gas in a liquid under constant temperature is directly
proportional to the partial pressure of the gas above the liquid but is
inversely proportional to the Henry's law constant (KH) for the gas. Henry's law can be expressed as:
where c is the
concentration (or solubility) of the gas in the liquid,
P is the partial pressure of the gas, and KH is Henry's law constant.
From the equation, it is clear that the solubility
of the gas is inversely related to
KH; if KH increases, the solubility decreases, and
vice versa.
In the given problem, you have the KH values of the gases A, B, and C as follows:
A: 145 kbar
B: 2×10−5 kbar
C: 35 kbar
Comparing the KH values:
Gas B has the lowest KH and hence the highest solubility.
Gas A, with the highest KH among the three, will have the lowest solubility.
Gas C has a KH value less than A but greater than B, so its solubility
will be lower than B but higher than A.
Therefore, the order of solubility of the gases in
water from the highest to the lowest is:
B > C > A
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